[(-32x-13)]/[(4x-7)(2x+8)]=[A/(2x+8)] + [B/(4x-7)]
Once you cross multiply it leads to:
-32x - 13= A(4x-7) + B(2x+8)
To find A and you can either use to cover up method or match up like coefficients which will lead to a system of equations. Here you should use the cover up method since this is simple.
Basically, you see that -4 and 7/4 cancel out one of the coefficients(A and B).
So, plugging x=-4 yields
-32(-4) - 13 = A(-4*4 - 7) + (2*-4 + 8)B
115= -23A, A= -5
Plugging x=7/4, you will get B
(-32*(7/4))-13=A[(4*(7/4)-7)] + B[(2*(7/4) + 8)]
-56 - 13 = A(0) + B[(7/2) + 8], -69=B[(7/2) + (16/2)]
-69=B(23/2), B= -69(2/23)= -6
A=-5, B= -6man wat grade r u in no one can answer this!!!!!!!Just "cheat" =)
Plug in x = -4 and solve for A (it'll make B disappear)
Then plug in x = 7/4 and solve for B (A will disappear)
That's it!i'm not really sure what u have to do but i know partial fractions is where u have something over a factorable polynomial equals A over a factor plus B over a factor plus C over a factor and so on and so forth